Question

Sin2x - sinx +2^1/2 cosx = (2^1/2)/2

Answer 1

(2sinx*cosx - sinx) + (√2*cosx - √2/2) = 0
2sinx*(cosx - 0.5) + √2*(cosx - 0.5) = 0
(cosx - 0.5)(2sinx + √2) = 0
1) cosx = 1/2
x = +-π/3 + 2πk
2) sinx = -√2/2
x = -π/4 + 2πk
x = -3π/4 + 2πk