<span>2a -( 14-3a)=-10
5а-4=0
а=0,8
</span>(9-2b)-(b+5)=16
-3b-12=0
b=-4
8,31y-71=1,11y=1
7,2y=72
y=72/7,2
y=10
2x^2 + 4x - 5 = 0
D = b^2 - 4ac = 16 + 40 = 56
x1 = ( - 4 + √56) / 4 = ( - 4 + 2√14)/4 = - 2(2 - √14) / 4 = - (2-√14)/2= -2+√14/2
x2 = ( - 4 - √56)/4 = (- 4 - 2√14)/4 = - 2(2+√14)/4= - 2 -√14/2
x1 + x2 = ( √14-2)/2 + ( - 2 - √14)/2 = - 4/2 = - 2
Ответ: d) - 2.