(x-3)^2 - 2x^2 +18 = 0
x^2 - 6x +9 - 2x^2 + 18 = 0
x^2 + 6x -27 = 0
D = 36 + 108 = 144
x1 = 3
x2 = - 9
2x^2=x
x(2x-1)-0
x=0
или
x=0,5
Решение
x = 2 + log₃ y
y^x = 3⁸
y^x = 3⁸
xlog₃ y = 8*log₃ 3
x = 8/log₃ y
8/log₃ y = 2 + log₃ y
log₃² y + 2*log₃ y - 8 = 0
log₃ y = t
t² + 2t - 8 = 0
t₁ = - 4
t₂ = 2
log₃ y = - 4
y = 3⁻⁴
y₁ = 1/81
log₃ y = 2
y = 3²
y₂ = 9
x = 8/log₃ y
x = 8/ (-4)
x₁ = - 2
x₂ = 8/2
x₂ = 4
Ответ: (- 2; 1/81) (4 ; 9)