1)(x-3)/[(2x-1)(x+3)]+9/[x-3)(x+3)]=[(x-3)²+9(2x-1)]/[(2x-1)(x²-9)]=
=(x²-6x+9+18x-9)/[(2x-1)(x²-9)]=(x²+12x)/[(2x-1)(x²-9)]
2)(x+12)/[x(x²-9)]*[(2x-1)(x²-9)]/[x(x+12)]=(2x-1)/x²
-57:(-19)= -3
-25*6= -150
-96:12= -8
36:(-18)= -2
16*(-4)= -64
80:(-16)= -5
-17*(-10)= 170
-95:19= -5
-81:(-27)= 3
-14*6= -83
<span> 0,5√32+5√8-⅓√18=2<span>√2+10√2-√2=11√2</span></span>
С^2 -25=0
(с-5)(с+5)=0
с= ± 5
х^2-121=0
(х-11)(х+11)=0
с= ± 11
-0,09+4х^2=0
4х^2 -0,09=0
(2х-0,3)(2х+0,3)=0
2х-0,3=0
2х=0,3
х1=0,15
2х+0,3=0
2х= -0,3
х2= - 0,15
х= ± 0,15
B₁=81 q=1/3
b₇=b₁*q⁷⁻¹=81*(1/3)⁶=3⁴*3⁻⁶=3⁴⁻⁶=3⁻²=1/9.