1)(с3-с2)-(3с+3с)=(с(3-2))-(3с(1+1)=(0.2•1)-(0.6•2)=0.2-1.2= -1
2)-(6х-2)+(3х-8)=-6х+2+3х-8= -3х -6= -3 •(-1.2) -6=3.6 - 6=-2.4
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Фотофотофотофотофотофотофото
![\dfrac{(x-5)(2x^2-4x+2)}{x+3} \leq 0 \\ \dfrac{2(x-5)(x-1)^2}{x+3} \leq 0](https://tex.z-dn.net/?f=+%5Cdfrac%7B%28x-5%29%282x%5E2-4x%2B2%29%7D%7Bx%2B3%7D+%5Cleq+0+%5C%5C++%5Cdfrac%7B2%28x-5%29%28x-1%29%5E2%7D%7Bx%2B3%7D+%5Cleq+0+)
Применяем метод интервалов:
___+___(-3)___-___1____-____5___+___
![x \in (-3; 5]](https://tex.z-dn.net/?f=x+%5Cin+%28-3%3B+5%5D)
Целые решения: -2; -1; 0; 1; 2; 3; 4; 5
17 3/22
Умножь 5 на 4 1/5 получишь 21
А затем вычти 3 19/22