5) b1=-32, b2=16, q=b2÷b1=16÷(-32)=-0,5
![s5 = \frac{b1( {q}^{5} - 1)}{q - 1} = \frac{ - 32( {( - 0.5)}^{5} - 1) }{ - 0.5 - 1} = \\ \frac{ - 32 \times ( - 1 \frac{1}{32} )}{ - 1.5} = \frac{ 33}{ - 1.5} = - 22](https://tex.z-dn.net/?f=s5+%3D++%5Cfrac%7Bb1%28+%7Bq%7D%5E%7B5%7D++-+1%29%7D%7Bq+-+1%7D++%3D++%5Cfrac%7B+-+32%28+%7B%28+-+0.5%29%7D%5E%7B5%7D+-+1%29+%7D%7B+-+0.5+-+1%7D++%3D++%5C%5C++%5Cfrac%7B+-+32+%5Ctimes+%28+-+1+%5Cfrac%7B1%7D%7B32%7D+%29%7D%7B+-+1.5%7D++%3D++%5Cfrac%7B+33%7D%7B+-+1.5%7D++%3D++-+22)
6) b1=1, b2=-1/2, q=b2/b1=-1/2÷1=-1/2
![s5 = \frac{1( {( - 0.5)}^{5} - 1}{ - 0.5 - 1} = \frac{ - 1 \frac{1}{32} }{ - 1.5} = \\ - \frac{33}{32} \div ( - \frac{3}{2} ) = \frac{33}{32} \times \frac{2}{3} = \frac{11}{16}](https://tex.z-dn.net/?f=s5+%3D++%5Cfrac%7B1%28+%7B%28+-+0.5%29%7D%5E%7B5%7D++-+1%7D%7B+-+0.5+-+1%7D++%3D++%5Cfrac%7B+-+1+%5Cfrac%7B1%7D%7B32%7D+%7D%7B+-+1.5%7D++%3D++%5C%5C++-++%5Cfrac%7B33%7D%7B32%7D++%5Cdiv+%28+-++%5Cfrac%7B3%7D%7B2%7D+%29+%3D++%5Cfrac%7B33%7D%7B32%7D++%5Ctimes++%5Cfrac%7B2%7D%7B3%7D++%3D++%5Cfrac%7B11%7D%7B16%7D+)
8) c1=1, q=-2
![s5 = \frac{1( {( - 2)}^{5} - 1}{ - 2 - 1} = \frac{ - 32 - 1}{ - 3} = \frac{ - 33}{ - 3} = 11](https://tex.z-dn.net/?f=s5+%3D++%5Cfrac%7B1%28+%7B%28+-+2%29%7D%5E%7B5%7D++-+1%7D%7B+-+2+-+1%7D++%3D++%5Cfrac%7B+-+32+-+1%7D%7B+-+3%7D++%3D++%5Cfrac%7B+-+33%7D%7B+-+3%7D++%3D+11)
y!=(sin(7x-1))!=cos(7x-1)*(7x-1)!=cos(7x-1)*7=7cos(7x-1)
0,000001=1:100000=10^(-6)
6√0,000001=10^(-1)=1/10
^ степень
6√ корень 6 степени
Решение методом подстановки
Всё в приложении.............