Question

Решите систему неравенств: \left \{ {{ \frac{4-3x}{2}\ \textgreater \ 2} \atop { x^{2}-64 \geq 0}} \right.

Answer 1

$\left \{ {{\frac{4-3x}{2}\ \textgreater \ 2} \atop {x^2-64 \geq 0}} \right. \; \; \left \{ {{4-3x\ \textgreater \ 4} \atop {(x-8)(x+8) \geq 0}} \right. \; \; \left \{ {{-3x\ \textgreater \ 0} \atop {x \leq -8,\; x \geq 8}} \right. \left \{ {{x\ \textless \ 0} \atop {x\in (-\infty ,-8\, ]\cup [\, 8,+\infty )}} \right. \\\\x\in (-\infty ,-8\, ]$