![\left \{ {{a_5-a_3=-4} \atop {a_2\cdot a_4=-3}} \right. \; \left \{ {{(a_1+4d)-(a_1+2d)=-4} \atop {(a_1+d)\cdot (a_1+3d)=-3}} \right. \; \left \{ {{2d=-4} \atop {a_1^2+4a_1d+3d^2=-3}} \right. \\\\ \left \{ {{d=-2} \atop {a_1^2-8a_1+12=-3}} \right. \; \left \{ {{d=-2} \atop {a_1^2-8a_1+15=0}} \right. \; \left \{ {{d=-2} \atop {a_1=3\; \; ili\; \; a_1=5}} \right.](https://tex.z-dn.net/?f=+%5Cleft+%5C%7B+%7B%7Ba_5-a_3%3D-4%7D+%5Catop+%7Ba_2%5Ccdot+a_4%3D-3%7D%7D+%5Cright.+%5C%3B++%5Cleft+%5C%7B+%7B%7B%28a_1%2B4d%29-%28a_1%2B2d%29%3D-4%7D+%5Catop+%7B%28a_1%2Bd%29%5Ccdot+%28a_1%2B3d%29%3D-3%7D%7D+%5Cright.+%5C%3B++%5Cleft+%5C%7B+%7B%7B2d%3D-4%7D+%5Catop+%7Ba_1%5E2%2B4a_1d%2B3d%5E2%3D-3%7D%7D+%5Cright.+%5C%5C%5C%5C+%5Cleft+%5C%7B+%7B%7Bd%3D-2%7D+%5Catop+%7Ba_1%5E2-8a_1%2B12%3D-3%7D%7D+%5Cright.+%5C%3B++%5Cleft+%5C%7B+%7B%7Bd%3D-2%7D+%5Catop+%7Ba_1%5E2-8a_1%2B15%3D0%7D%7D+%5Cright.+%5C%3B++%5Cleft+%5C%7B+%7B%7Bd%3D-2%7D+%5Catop+%7Ba_1%3D3%5C%3B+%5C%3B+ili%5C%3B+%5C%3B+a_1%3D5%7D%7D+%5Cright.+)
Ответ: две прогрессии, где
![a_1=3\; ,\; d=-2](https://tex.z-dn.net/?f=a_1%3D3%5C%3B+%2C%5C%3B+d%3D-2)
и
![a_1=5\; ,\; d=-2](https://tex.z-dn.net/?f=a_1%3D5%5C%3B+%2C%5C%3B+d%3D-2)
.
1) 5x-5+7≤1-3x-6
5x+2≤3x-5.
2)4a+32-7a+7<12
-3a+39<12.
3)4b-6-1.2≥6b-1
4b-7.2≥6b-1
4) 1.7-3+3m≤-m+1.9
-1.3+3m≤m+1.9
92^5=64
2^5=8^2
0,2^6=0,04
0,2^6=0,2^2
3^4=81
3^4=9^2
6^12=36
6^12=6^2
0,25^7=1/64
0,25^7=(1/8)^2
0,0001=0.1^5
0,01^2=0,1^5
______________________
Готово!!Желаю удачи!!
Первая функция это окружность с радиусом 5
Вторая функция прямая
Ctg²x·(3-3cos²x)=ctg²x·3(1-cos²x)=ctg²x·3·sin²x=
=
![\frac{ cos^{2}{x} }{ sin^{2}{x} }](https://tex.z-dn.net/?f=+%5Cfrac%7B+cos%5E%7B2%7D%7Bx%7D+%7D%7B+sin%5E%7B2%7D%7Bx%7D+%7D+)
·3·sin²x=3cos²x=3·0,1²=3·0,01=0,03