Question

Сократите дробь p(b)/p(1/b), если p(b)=(b+3/b)(3b+1/b)

Answer 1

$\frac{p(b)}{p(1/b)}= \frac{(b+ \frac{3}{b} )(3b+\frac{1}{b})}{(\frac{1}{b}+ 3b )(\frac{3}{b}+b)}= 1$

Answer 2

P(b)=(b²+3)(3b²+1)/b²
p(1/b)=(1/b +3b)(3/b+b)=(1+3b²)(3+b²)/b²
p(b)/p(1/b)=(b²+3)(3b²+1)/b² : (1+3b²)(3+b²)/b²=
=(b²+3)(3b²+1)/b²*b²/(1+3b²)(3+b²)=1