Y=3|x-2|+|x+3|x-2=0 x=2
x+3=0 x=-3
x-2 | - | - | +
x+3| - | + | +
x ∈ (-><;-3)
-3х+6-х-3=y
y=-4x+3
y=0|1|2|
x=3|-1|-5|
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x ∈ (-3;2)
-3х+6+х+3=y
y=-2х+9
y=0|1|2|
x=9|7|5|
-----------------------
x ∈ (2;+><)
3х-6+х+3=y
y=4х-3
y=0|1|2|
x=-3|1|5|
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Дальше просто строите график по точкам.
2x>|x|+1
x≤0
2x>-x+1
3x>1
x>1/3 ∉
x≥0
2x>x+1
x>1
Ответ: x∈(1;+∞).
(b-2)³=b³-6b²+12b²-8=b³+6b²-8
(a-b)³=a³-3a²b+3ab²-b³
( V 2 ) ^ x • ( V 7 ) ^ x = 196
V 14 ^ x = 196
14 ^ 1/2x = 14 ^ 2
1/2x = 2
X = 2 : ( 1/2 )
X = 4
8х^3+8x^2+14x-8x^2=8x^3+14x
Якщо x=0,5:
8*0,125+7=1+7=8