<em>n³+3n²+5n+3=3((n³/3)+n²+(5n/3)+1)=3((n³+5n)/3+n²+1). - значит делится на 3, блеа!!!</em>
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<span>√(54/125</span><span><span>) = <span>√(6*9/5*25</span><span><span>) = </span></span><span>3/5 √(6/5</span><span><span>) </span></span>
</span></span>
<span>√(248/128</span><span><span>) = <span>√(124/64</span><span><span>) = </span></span><span><span><span>√(31/16</span><span><span>) = </span></span></span></span>1/4 <span><span><span>√(31</span><span><span>) </span></span></span></span>
</span></span>
<span>√(13/32</span><span><span>) = <span>√(13/2*16</span><span><span>) = </span></span><span>1/4 √(13/2</span><span><span>)</span></span>
</span></span>
<span>√(17/81</span><span><span>) = 1/9 <span>√(17</span><span><span>) </span></span>
</span></span>
Ответ:
(0; - 8)
Объяснение:
Ось ординат - ось у, в точке пересечения с осью у х = 0
Приравниваем:
у = 1/2*0 - 8
у = - 8
Значит координата точка пересечения графика функции с осью ординат имеет координаты (0; - 8)