1)<span>3х⁴-<span>5х³-x вроде</span></span>
<span><span>2) <span> х²-7,5х+4,5х³-2х²+1,5х-ху²+4х²у-2х²у= -х² +4,5х³-6х +х²у= -2² + 4,5 * 2³ -6 * 2+2² * -1= 4+36-12-4=24</span></span></span>
6х+2х+9х+3=11х+30
17х-11х=27
17 х в квадрате -11х=27
Стороны прямоугольника через диагональ :
2*
![d^{2}](https://tex.z-dn.net/?f=+d%5E%7B2%7D+)
= 2*
![a^{2}](https://tex.z-dn.net/?f=+a%5E%7B2%7D+)
+ 2*
![b^{2}](https://tex.z-dn.net/?f=+b%5E%7B2%7D+)
d= корню из (
![a^{2}](https://tex.z-dn.net/?f=+a%5E%7B2%7D+)
+
![b^{2}](https://tex.z-dn.net/?f=+b%5E%7B2%7D+)
)
![a^{2} + b^{2}](https://tex.z-dn.net/?f=+a%5E%7B2%7D+%2B+b%5E%7B2%7D+)
= 61
Система уравнений:
2a+2b=22 первое разделим на 2
![a^{2} + b^{2}](https://tex.z-dn.net/?f=+a%5E%7B2%7D+%2B+b%5E%7B2%7D+)
= 61
Метод подстановки:
a=11-b =>
![(11-b)^{2} + b^{2}](https://tex.z-dn.net/?f=+%2811-b%29%5E%7B2%7D+%2B+b%5E%7B2%7D+)
= 61
121-22b+
![b^{2}](https://tex.z-dn.net/?f=+b%5E%7B2%7D+)
+
![b^{2}](https://tex.z-dn.net/?f=+b%5E%7B2%7D+)
=61
-22b+
![b^{2}](https://tex.z-dn.net/?f=+b%5E%7B2%7D+)
+
![b^{2}](https://tex.z-dn.net/?f=+b%5E%7B2%7D+)
= -60
-22b+2*
![b^{2}](https://tex.z-dn.net/?f=+b%5E%7B2%7D+)
+60=0 (кв. ур.)
D=484 - 480=4 =>
![\sqrt{D}](https://tex.z-dn.net/?f=+%5Csqrt%7BD%7D+)
= 2
b1=(22+2)/4=6 при b=6 a=5 S= 30
b2=(22-2)/4=5 при b=5 a=6 S=30