1)<span>cosa=u*(m+M)/mv=0.2*(80+720)/80*4=0,2*800/320=0,5
a=60гр
2)y`=8x-10+2/x=(8x²-10x+2)/x=0
2(4x²-5x+1)=0
D=25-16=9
x1=(5-3)/8=1/4∉[0;3;3]
x2=(5+3)/8=1∈[0,3;3]
y(0,3)=4*0,09-10*0,3+2ln0,3 -5≈0,36-3+2*(-1,2)-5≈-10,04
y(1)=4*1-10*1+2ln1-5=4-10+0-5=-11-наим
y(3)=4*9-10*3+2ln3-5≈36-30+2*1,1-5≈3,2</span>
X^3/3+1 =10
x^3/3 = 10-1
x^3/3 = 9
x^3 = 9*3
x^3 = 27
x = 3
<span>(x+6)(x+3) <0
х</span>₁= -6 , х₂=-3
х∈ ( -6; -3)
Ответ: <span>х∈ ( -6; -3)</span>
Вот, надеюсь разберете)))))
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