Question

Упростить выражение (6\у^2-9+1\3-у)*у^2+6у+9\5

Answer 1

$(\frac{6}{y^2-9}+ \frac{1}{3-y})* \frac{y^{2}+6y+9}{5}=(\frac{6}{(y-3)(y+3)}-\frac{1}{y-3})* \frac{(y+3)^{2}}{5}= \\ =\frac{6-y-3}{(y-3)(y+3)}*\frac{(y+3)^{2}}{5}=\frac{(3-y)(y+3)^{2}}{(y-3)(y+3)5}= \frac{-(y-3)(y+3)}{(y-3)5}= -\frac{y+3}{5}$