Sin² x - 6 cos² x - 5sinx*cosx=0
ДЕЛИМ НА COS²X
tg²x-5tgx-6=0
D=25+24=49; √D=7
tgx=(5+7)/2=6; tgx=-1
x=arctg6+πn.... x=-π/4+πn
3u-2v=12 [x4
4u+3v=-1 [x-3
12u-8v=48
-12u-9v=3
12u-8v-12u-9v = 48+3
-17v = 51
v = -3
из 1 уравнения: u = (12+2v)/3=(12+2*(-3))/3=2
ответ: u=2, v=-3
"""""""""""""""""""""""""""""""""""""""""