(x^2+3x)=y
(y-20)(y+2)=240
y^2-18y-280=0
D=324-4*(-280)=1444
y1=28
y2=-10
x^2+3x-28=0 x^2+3x+10=0
D=121 D=-31
x1=4 Реш нет
x2=-7
Ответ:-7; 4
6x^2-3xy+5x-8y+2 = (6x^2+5x+2 ) - (<span>3xy+8y)</span>
4ц1/6 *x^8 * y^5 * (-1ц(1/5) * x^5 * y)^3 = 25/6 * x^8 * y^5 * (-6/5 *x^5*y)^3 =
=25/6 * x^8 *y^5 * ((-6)³/5³) * x^15 * y^3 = -36/5 * x^23 * y^8