1a) 5x + (3x - 7) = 9 б) 3y - (5 - y) = 11 в) 48 = 11 - (9a + 2)
5x + 3x - 7 = 9 3y - 5 + y = 11 48 = 11 - 9a - 2
8x = 9 + 7 4y = 11 + 5 9a = 9 - 48
8x = 16 4y = 16 9a = - 39
x = 2 y = 4 a = - (4)1/3
г)13 - (5x + 11)= 6x
13 - 5x - 11 = 6x
- 5x - 6x = 11 - 13
- 11x = - 2
x = 2/11
2a) (7x + 1) - (6x + 3) = 5
7x + 1 - 6x - 3 = 5
x = 5 - 1 + 3
x = 7
б)(8x + 11) - 13 = 9x - 5
8x + 11 - 13 = 9x - 5
8x - 9x = - 5 - 11 + 13
- x = - 3
x = 3
в) 2 = (3x - 5) - (7 - 4x)
2 = 3x - 5 - 7 + 4x
- 3x - 4x = - 5 - 7 - 2
- 7x = - 14
x = 2
г) 8x + 5 = 119 + (7 - 3x)
8x + 5 = 119 + 7 - 3x
8x + 3x = 119 + 7 - 5
11x = 121
x = 11
Сos(t - 2π) = cos(2π - t) = cost
cos^2t = 1/(tg^2t + 1)
cos^2t = 1/(5/4 + 1)
cos^2t = 4/9
cost = -(2/3)
cost = (2/3)
ctg(-1) = - ctgt, tgt = -√5/2, tgt*ctgt = 1,ctgt = 1/tgt, ctgt = 1/(-√5/2)
sin(4π - t) = sint
sint = √(1 - cos^2x) = √[1 - (2/3)^2] = √5/3
Ответы на вычисление:
1) -58
2) 5
3) 1/9
4sin2x=7cos²x-<span>7sin²x
</span>
4sin2x=7·(cos²x-<span>sin²x)
</span>4sin2x=7·cos2x
Делим на сos2x≠0
tg2x=7/4
2x=arctg(7/4)+πk, k∈Z<span> <span>
x=(1/2)</span></span>arctg(7/4)+(π/2)·k, k∈Z<span> </span><span>
или
</span><span>7sin²x+4·2sinx·cosx-7cos²x=0
Делим на cos²x≠0
7tg²x+8tgx-7=0
D=64-4·7·(-7)=64+196=260
tgx=(-8-2√65)/14 или tgx=(-8+2√65)/14</span>
tgx=(-4-√65)/7 или tgx=(-4+√65)/7
х=artcg(-4-√65)/7 + πn, n∈Z или х=artcg(-4+√65)/7 + πm, m∈Z