y(x)=1/√(x-1)
y'(x)=(1/√(x-1))'=(1'*√(x-1)-1*(√(x-1))')/(√(x-1))²=(0-(1/(2*√(x-1))/(x-1)=-1/(2*√(x-1)³).
22/(х-3)=3/(х-22)
22*(х-22)=3*(х-3)
22х - 484 = 3х - 9
22х - 3х = 484 - 9
19х = 475
х = 475/19
х= 25
2у+2-3у=10-7
2у-3у+2=3
2-у=3
у=1
Скорее всего так.
2)y'=12*1/12*x^11+3*1/3*x^2+1
y'=x^11+x^2+1=tg a
tg(-1)=(-1)^11+(-1)^2+1=1
tg a=1
a=arctg1=45
3)f'(x)=3x-TT/2+4sinx
f'(TT/6)=3*TT/6-TT/2+4sinTT/6=TT/2-TT/2+4*1/2=2
4)v=s'(t)=4t^3-4t
v=s'(3)=4*27-4*3=108-12=96
5)f'(x)=12x-3x^2
12x-3x^2>0
3x(4-x)>0
x=0 x=4
x э (0;4)