X^2 + px - 32 = 0
8^2 + p*8 - 32 = 0
8p = - 32
p = - 4
x^2 - 4x - 32 = (x - 8)(x + 4)
x2 = - 4
x1 = 8
Y = <u>√(4x-x²+12)</u>
√(3-x)
{4x-x²+12≥0
{3-x>0
4x-x²+12≥0
x² -4x -12≤0
x² -4x -12=0
D=16+48=64
x₁=<u>4-8 </u>= -2
2
x₂ =<u>4+8</u> =6
2
+ - +
-------------- -2 -------------- 6 --------------------
\\\\\\\\\\\\
x∈[-2; 6]
3-x>0
-x>-3
x<3
\\\\\\\\\\\\\\\\\\\\\\\
------------- -2 -------- 3 ------------------ 6 -------------
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
x∈[-2; 3)
Ответ: 2)