(5m²y³+ 3m³y²- m) - (3m²y³ + 2m + 3m³y²) = 5m²y³ + 3m³y² - m - 3m²y³ - 2m -
- 3m³y² = 2m²y³ - 3m
B
A H C
BH = 11√3
В равностороннем треугольнике все углы по 60° . Из прямоугольного ΔABH :
![Sin<BAH = \frac{BH}{AB}\\\\AB=\frac{BH}{Sin60^{o} } =\frac{11\sqrt{3} }{\frac{\sqrt{3} }{2} }=\frac{22\sqrt{3} }{\sqrt{3} }=22\\\\P_{ABC}=22*3=66](https://tex.z-dn.net/?f=Sin%3CBAH+%3D+%5Cfrac%7BBH%7D%7BAB%7D%5C%5C%5C%5CAB%3D%5Cfrac%7BBH%7D%7BSin60%5E%7Bo%7D+%7D+%3D%5Cfrac%7B11%5Csqrt%7B3%7D+%7D%7B%5Cfrac%7B%5Csqrt%7B3%7D+%7D%7B2%7D+%7D%3D%5Cfrac%7B22%5Csqrt%7B3%7D+%7D%7B%5Csqrt%7B3%7D+%7D%3D22%5C%5C%5C%5CP_%7BABC%7D%3D22%2A3%3D66)
1)5х^2+14x-3=0
D=196-4 *5*(-3) =256=16
x1=-14 + 16\ 10=0,2
x2=-14-16/10 =3
2)x^2-2x+2=0
D=4-4*1*2=-4=-2
x1=2+(-2)\2=0