2x^2-8x=0
2x(x-4)=0
2x=0 или x-4=0
x=0 х=4
Ответ: 0;4
А) 5x^6y - 5x^4y^2 - 10 x^3y = 5x^3y(x^2 - xy^2 - 2)
<span>б) 4x - x^2 + y^2 - 4y = 4(x-y) - ( x-y)(x+y) = (x-y)(4-x-y)</span>
..............................
4*(cos^2 x -sin^2 x)= 4*(1-2sin^2x) = 4*(1-2*0,5^2) = 4*(1-0,5)=4*0,5 = 2
ответ:2