(2^-17 * 2^12) / 2^-9 = (2^-5) / 2^-9 = 2^4 = 16
<em>х⁴*у⁴/((х²)²)=у⁴, при условии х≠0</em>
<em>у⁴=16</em>
<em>у=±2</em>
<em>Ответ у₁=2</em>
<em> у₂=-2</em>
Cos(8x-π/8)≥√3*21/42
cos(8x-π/8)≥√3/2
2πn-π/6≤8х-π/8≤2πn+π/6, n∈Z
2πn-π/6+π/8≤8х≤2πn+π/6+π/8
2πn-π/24≤8х≤2πn+7π/24
πn/4-π/192<span>≤х≤πn/4+7π/192
</span>x∈[πn/4-π/192; <span>πn/4+7π/192</span>]
(y-4)(y+4)/3(y+4)=(y-4)/3
<span>1) 3 ax =12-x
х= -9
подставим в уравнение
3а·(-9)=12-(-9)
-27а=21
а=-21/27
а=-7/9
2) (5a+2)x=8-2a
х= 2
подставим в уравнение
(5а+2)·2=8-2а
10а+4=8-2а
12а=4
а=1/3
</span>