= 2x³+10x²+6x
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В функции y=f(x), x — аргумент функции, y — значение
Подставим вместо х 4.
y = -3(4) + 4 = -12 + 4 = -8
Cos^2(90+60)-(sin70cos40-cos70cos(90-40))^2=3/4-(sin70cos40-cos70sin40)^2=
3/4-1/4=1/2
1.(1.5x-8y)^2=( (1.5)^2 - 2*1.5x*8y+(8y)^2)=2.25x^2-24xy+64y^2
2.(-4+5y)^2=( (-4)+2*(-4)*5y+5y=16-40y+25y^2