Question

Помогите пожалуйста сделать номер 267 (в,г)

Answer 1

Sin²4x - 3sin4x + 2 = 0
a = sin4x, -1 ⩽ a ⩽ 1
a² - 3a + 2 = 0
a² - 2a - a + 2 = 0
(a - 2)(a - 1) = 1
a₁ = 1, [a₂ = 2]!
sin4x = 1
4x = π/2 + 2πn, n ∈ ℤ
x = π/8 + πn/4, n ∈ ℤ