В знаменателе имеем sin^2 11+cos^2 11 = 1. 34/1=34
Ответ: 34.
Уверена 100% что правильно
Решение
<span>S</span>₅ <span>= 1/2(a</span>₁ <span>+ a</span>₅<span>)•5 = 1/2(a</span>₁ <span>+ a</span>₁ <span>+ 4d)•5 = (a</span>₁ <span>+ 2d)•5
</span><span>S</span>₆₋₁₀ <span>= 1/2(a</span>₆ <span>+ a</span>₁₀<span>)•5 = 1/2(a</span>₁ <span>+ 5d + a</span>₁ <span>+ 9d)•5 = (a</span>₁ <span>+ 7d)•5
</span><span>Найдём разность этих сумм, она равна 200
</span><span>5(a</span>₁ <span>+ 2d) - 5(a</span>₁ <span>+ 7d) = 200</span><span>a</span>₁ <span>+ 2d - a</span>₁ <span>- 7d = 40
</span><span>- 5d = 40
</span><span>d = - 8
</span><span>Аналогично найдём разность суммы с 1 по 10 и с 11 по 20
</span><span>10•1/2(а</span>₁ <span>+ а</span>₁₀<span>) - 10•1/2(а</span>₁₁ <span>+ а</span>₂₀<span>) =
</span><span>= 5(a</span>₁ <span>+ a</span>₁ <span>+ 9d) - 5(a</span>₁ <span>+ 10d + a</span>₁ <span>+ 19d) = 5(9d - 29d) =
= 5(- 20d) =</span><span> 5(- 20)*(- 8) = 800
</span><span>Ответ: 800</span>