Решение7/7-х. + х^2+49/х^2-49 при х= - 14.
7/(7 - х). + (х^2 + 49)/(х^2 - 49) = 7 / (7 - x) - (x² + 49) / [(7 - x)*(7 + x)] == [7*(7 + x) - x² + 49] / [(7 - x)*(7 + x)] = [49 + 7x - x² - 49] / [(7 - x)*(7 + x)] == [x*(7 - x)] / [(7 - x)*(7 + x)] = x / (7 + x)при х= - 14. - 14 / (7 - 14) = - 14/(-7) = 2
Ответ:
=12a²+4ab-6ab-2b²-12a²-10ab+2b²=-12ab
А) =(10х+3)²
Ответ: 1)
б) =(¹/₃ у-3х)²=(¹/₃* (-27)-3*11)²=(-9-33)²=(-42)²=1764
6х+18-х+4=1,6-х
6х-х+х=1,6-4-18
6х=20,4
х=3,4
22.б=0,4m
Г=0,6х
23.б=...=2x/10y=0,2xy
Г=...6m/4n=1,5mn
24.б=...=5(2m-n)/5n=2m-n/n
Г=...=2(ab-c)/2(ac-b)=ab-c/ac-b
25.б=...=x/x(y-1)=1/y-1
Г=...=аb(a+1)/ab=a+1
(...)-это данная дробь