<span>f(x)=√9x + 5 = </span>√9 * x^1/2 + 5 = 3x^1/2 + 5;
f(x)` = 3 * 1/2 * x^(-1/2) =
3/2
= -------;
√x
(x^2-5x)(x^2-5x+10)+24=0
Замена: x^2-5x=t
t(t+10)+24=0
t^2+10t+24=0
D=4 t1=-4, t2=-6
x^2-5x=-4 x^2-5x=-6
x^2-5x+4=0 x^2-5x+6=0
x1=1, x2=4 x3=2, x4=3
Sin(6x+x)=1/2
sin7x=1/2
7x=(-1)^n*π/6+πn
x=(-1)^n*π/42+πn/7,n∈z