Question

X^4-4.36x^2+1.44=0 биквадратное уравнение

Answer 1

$x {}^{4} - 4.36x {}^{2} + 1.44 = 0 \\ x {}^{2} = y \\ y {}^{2} - 4.36y + 1.44 = 0 \\ d = 19.0096 - 5.76 = 13.2496 \\ y = \frac{4.36 + 3.64}{2} = 4 \\ y = \frac{4.36 - 3.64}{2} = 0.36 \\ x {}^{2} = 4 \\ x = 2 \\ x = - 2 \\ x {}^{2} = 0.36 \\ x = 0.6 \\ x = - 0.6$