Question

24 вариант . ( 5/4x + 1/12x ) * x^3/32 при х =-6 27 вариант . 3/p - p+12k/4pk при p = √5 , k = 1/6

Answer 1

24 вариант.
$(\frac{5}{4x} + \frac{1}{12x} ) * \frac{x^3}{32} = \frac{5*3+1}{12x} * \frac{x^3}{32} = \frac{16x^3}{12x*32} = \frac{16x *x^2}{16x * 2*12} = \frac{x^2}{24} \\ \\ x=-6 \\ \frac{(-6)^2}{24} = \frac{36}{24} = \frac{3}{2} =1.5$

27 вариант.
$\frac{3}{p} - \frac{p+12k}{4pk} = \frac{3*4k - (p+12k)}{4pk} = \frac{12k -p-12k}{4pk} = \frac{-p}{4pk} = - \frac{1}{4k} \\ \\ p= \sqrt{5} ; k= \frac{1}{6} \\ - \frac{1}{4* \frac{1}{6} } = - \frac{1}{ \frac{1}{3} } = -1 : \frac{1}{3} = -1* \frac{3}{1} = -1*3 = -3$