Х<span>²-17х+16=0
По теореме Виета: х1 = 1;
х2 = 16
Ответ: х=16</span>
1)2⁵×(2⁻²)*ˣ=2⁷ х=-1 2⁵×(2⁻²)⁻¹=2⁵⁺⁽⁻²⁾*⁽⁻¹⁾ =2⁷<span>
2)4</span>⁵×8⁻²*ˣ =4⁷ ⇒ 2¹⁰ × 2⁻⁶*ˣ =2¹⁴ х=(14-10)/-6= -2/3
2¹⁰ × 2⁻⁶* ⁽⁻²/³) =2¹⁰ ⁺ ⁽⁻⁶⁾*⁽⁻²/³⁾ =2¹⁴ <span>
3)5</span>⁵×5 ⁻² /ˣ=5⁷ х=-1 5⁵×5 ⁻² /⁽⁻¹⁾=5⁵⁺²=5⁷
A)5a³ *9a^4=45a^7
b)16x²-24xy+9y²-4x²+y²=12x²-24xy+10y²
(cosx+cos (pi/2+x))/(2cos^2x-sin2x)=(cosx-sinx)/(2cos^2x-2sinxcosx)=(cosx-sinx)/(2cosx(cosx-sinx)=1/2cosx