-6a^2+3б
8х^5у+5х^3у^3-2х^2у^2
2х^2-4х+3х-6=2х^2-х-6
у^3+3у^2+у^2+3у-6у-18=у^3+4у^2-3у-18
Sin(α + β) = sinα · cosβ + cosα · sinβ
sin(π/3 + α) - √3/2cosαα α = 0,
sinπ/3 · cosα + cosπ/3 · sinα - <span>√3/2cosαα α = 0,
</span>√3/2cosαα α + cosπ/3 · sinα - <span>√3/2cosαα α = 0,
</span><span>cosπ/3 · sinα = 0,
</span>1/2 · <span>sinα = 0,
</span><span>sinα = 0,
</span>α = πn, n ∈ Z
<span>(6а-7)^2-(4а-2)^2=(6a-7+4a-2)(6a-7-4a+2)=(10a-9)(2a-5)</span>
Для того что бы найти t , решаем уравнение:
![\sin t= \frac{ \sqrt{3} }{2} \\t=(-1)^n\arcsin \frac{ \sqrt{3}}{2}+\pi n,n\in\mathbb Z\\t= (-1)^n \frac{\pi}{3}+\pi n ,n\in Z](https://tex.z-dn.net/?f=%5Csin+t%3D+%5Cfrac%7B+%5Csqrt%7B3%7D+%7D%7B2%7D++%5C%5Ct%3D%28-1%29%5En%5Carcsin++%5Cfrac%7B+%5Csqrt%7B3%7D%7D%7B2%7D%2B%5Cpi+n%2Cn%5Cin%5Cmathbb+Z%5C%5Ct%3D+%28-1%29%5En+%5Cfrac%7B%5Cpi%7D%7B3%7D%2B%5Cpi+n+%2Cn%5Cin+Z+)
Остальное во вложении.