Question

Розвяжите систему уравнений x^2+xy=10 2x+y=-3 Срочно

Answer 1

$\left \{ {{x^{2}+x y=10} \atop {2x+y=-3}} \right.\\\\\left \{ {{y=-2x-3} \atop {x^{2}+x(-2x-3)-10=0 }} \right.\\\\\left \{ {{y=-2x-3} \atop {x^{2}-2x^{2} -3x-10=0 }} \right.\\\\\left \{ {{y=-2x-3} \atop {x^{2}+3x+10=0 }} \right.\\\\x^{2}+3x+10=0\\\\D=3^{2}-4*10=9-40=-31<0$

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