(6x-5)^3=x^6
(6x-5)^3= (x^2)^3
6x-5=x^2
6x-5-x^2=0
x^2-6x+5=0
D= b^2-4ac= (-6)^2-4*1*5=16
x1= (6-4)/2=1
x2=(6+4)/2=5
Или по теореме Виета:
x1+x2= -b/a= 6(1+5=6)
x1*x2=c/a=5(1*5=5)
Ответ:1;5
Кратных 11 : {110,121,132,143,154,165,176,}
110+121+132+143+154+165+176=1001
Множества совпадают тогда , когда
![aa_{1} = bb_{1} \\ aa_{2} = bb_{2} \\ ... \\ aa_{n} = bb_{n} \\\\ \frac{a}{b} = \frac{b_{1}}{a_{1}} = \frac{b_{2}}{a_{2}} ... = \frac{b_{n}}{a_{n}} \\ b_{n} = ax \\ a_{n} = bx \\ ](https://tex.z-dn.net/?f=++aa_%7B1%7D+%3D+bb_%7B1%7D+%5C%5C%0A+++++++aa_%7B2%7D+%3D+bb_%7B2%7D+++++++%5C%5C%0A++++++++++++...+%5C%5C%0A+++++++++aa_%7Bn%7D+%3D+bb_%7Bn%7D+++++%5C%5C%5C%5C%0A+%5Cfrac%7Ba%7D%7Bb%7D+%3D+%5Cfrac%7Bb_%7B1%7D%7D%7Ba_%7B1%7D%7D++++%3D++%5Cfrac%7Bb_%7B2%7D%7D%7Ba_%7B2%7D%7D+...+%3D+%5Cfrac%7Bb_%7Bn%7D%7D%7Ba_%7Bn%7D%7D+++++++++%5C%5C%0A+b_%7Bn%7D+%3D++ax++++++++++++++++++++++++++++%5C%5C%0A+a_%7Bn%7D+%3D+bx+%5C%5C+++%0A%0A+++++++++++++++++++++++++++++++++++++++++++++++++++%0A%0A++++++++)
То есть все пары
![a \in \ a ; bx\\ b \in b ; ax \\ x \in N](https://tex.z-dn.net/?f=++a+%5Cin+%5C+a+%3B+bx%5C%5C%0A+++++b+%5Cin+b+%3B+ax+%5C%5C%0A++++++++x+%5Cin+N)