Question

2sin(pi+t)+cos(pi/2-t)=-1/2

Answer 1

 

$2sin(\pi+t)+cos(\pi/2-t)=-1/2\\ 2sin(\pi+t)+sin(t) = -1/2\\ -2sin(t)+sin(t) = -1/2\\ -sin(t) = -1/2\\ sin(t) = 1/2\\ t = \pi/6 + 2\pi n\\ t = 5\pi/6 + 2\pi n$

 

Answer 2

-2sin t + sin t= -1/2

- sin t= -1/2

sin t= 1/2

(t=pi / 6)вроде так