(g-y)²-g²-y²+4d-18d-7(1-2d)=3
g²-2gy+y²-g²-y²+4d-18d-7+14d=3
g²-2gy+y²-g²-y²+4d-18d+14d=3+7
-2gy=10
3x-2y-11=03(<span>2-y</span>)-2y-11=0
6-3y-2y-11=0
-5y-5=0 /:(-5<span>)
y+1=0
y=-1
</span>x=2-y=2-(-1)=3
(x+3)(x-7)/(2-x)>0 ОДЗ: 2-x≠0 x≠2
x+3=0 x₁=-3 2-x=0 x₂=2 x-7=0 x₃=7 ⇒
-∞____+____-3____-____2____+____7____-____+∞
Ответ: x∈(-∞;-3)U(2;7).