<span>1)y=cos(3x+2) = cos3x*cos2-sin3x*sin2</span>
<span>y' = (cos3x*cos2-sin3x*sin2)' = (cos3x*cos2)' - (sin3x*sin2)' = (cos3x)' *cos2+cos3x*(cos2)' - (sin3x)' *sin2+sin3x*(sin2)' = -sin3x*cos2-cos3x*sin2-cos3x*sin2+sin3x*cos2=-2cos3x*sin2</span>
<span>2)<span>y=-x^3-2sin2x = -3x² - 4cos2x</span></span>
5^(x²-4x)*(5+1)=30
5^(x²-4x)*6=30
5^(x²-4x)=5
x²-4x=1
x²-4x-1=0
D=16+4=20
x1=(4-2√5)/2=2-√5
x2=2+√5
10/(5-х)(5+х) - 1/(5+х)-(-х)/-(х-5)= 0,10 /(5-х)(5+х)-1/(5+х)+х(-х+5) =0,10 -1(5-х) + х(5-х)= 0,10 -5 + х +5х- х(2)=0,-х(2)+ 6х + 5 =0,х(2)- 6х -5=0,D= 36-20=16,х1 = 6-4/ 2умноженное на1 = 1,х2 = 6+4 / 2 умнож. на1 = 5.ОДЗ не равно 5.<span>Ответ : 1.</span>