x³-x²-x²-6x+x+6=0
x²(x-1)-6(x-1)-x(x-1)=0
(x-1)(x²-6-x)=0
x1=1
x²-x-6=0
D= 1+24=25
x2= (1+5)/2= 3
x3= (1-5)/2= -2
Ответ: x1= 1, x2= 3, x3= -2
<em>sin(x+π/2)=0</em>
<em>x+π/2=πn; n∈Z</em>
<em>x=π/2+πn; n∈Z</em>
Ответ 4.
а1=60/5=12
а2=60/6=10
а3=60/7=8,5..
а4=60/8=7.5
а5=60/9=6,6...