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1) D(f) (-бесконечность; +бесконечность)
2) х-5>=0
x>=5
D(f) [5; +бесконечность)
А)4х2+8х> 4х(х+2)
б) 3m-6n+mn-2n2> 3(m-2n)+n(m-2n)
3 - 4sin²(3x + π/3) = 0
3 = 4sin²(3x + π/3)
sin²(3x + π/3) = 3/4
sin(3x + π/3) = ±√3/2
1) sin(3x + π/3) = √3/2
3x + π/3 = (-1)ⁿπ/3 + πn, n ∈ Z
x = (-1)ⁿπ/9 - π/9 + πn/3, n ∈ Z
2) sin(3x + π/3) = -√3/2
3x + π/3 = (-1)ⁿ+¹π/3 + πn, n ∈ Z
x = (-1)ⁿ+¹π/9 - π/9 + πn/3, n ∈ Z