2sin(pi/10x)+1=0
sin(pi/10x)=-1/2
pi/10x=(-1)^k+1*pi/6+pik
x=(-1)^k+1*pi/6+10/pi+10k, k∈Z
1 - 2х + х² = 0
х² - 2х + 1 = 0; D = 4 - 2 = 2
x₁ = (2 - √2)/2 = 2/2 - √2/2 = 1 - 1/√2
x₂ = (2 + √2)/2 = 1 + 1/2
26 + 3x - 5x² = x - 1
26 + 3x - 5x² - x + 1 = 0
27 + 2x - 5x² = 0
-5x² + 2x + 27 = 0
D = 2² - 4 * (-5) * 27 = 4 + 540 = 544
√D = √16*34 = 4√34
x₁ = (-2 - 4√34) / -10 = -2(1 + 2√34) / -10 = (1 + 2√34) / 5
x₂ = (-2 + 4√34) / -10 = -2(1 - 2√34) / -10 = (1 - 2√34) / 5
2x⁴-3x²+1=0
2x⁴-2x²-x²+1=(2x⁴-2x²)-(x²-1)=0
2x²(x²-1)-(x²-1)=0
(x²-1)(2x²-1)=0
1)x²-1=0
x²=1
x=±1
2)2x²-1=0
2x²=1
x²=1/2
x=±√1/2
Ответ:...........................
1) (-2.4) во 2 степени
2)3/4 в 3 степени
3)7/8 во 2 стпени
4)2.3 в 3 степени