(x²+4x+4)(x²-6)=x⁴<span>+x</span><span>²</span><span>(−6)+4x</span><span>³</span><span>−24x+4x</span><span>²</span><span>−24=x</span><span>⁴</span><span>+</span><span>x²</span><span>(−6)</span><span>+</span><span>4</span><span>x</span><span>³</span><span>−</span><span>24</span><span>x</span><span>+</span><span>4</span><span>x</span><span>²</span><span>−</span><span>24</span><span>=</span>x⁴−2x²+4x³−24x−24=x⁴+4x³−2x²−24x-<span>24 </span>Ответ:x⁴+4x³−2x²−24x−24≥0⇒решить данное неравенство невозможно, т.к многочлен в левой части не в первой ( Ax+B ) и не во второй степени ( Ax² + Bx + C ).
2*a^2*b^3=9
-6a^2*b^3=-3*2a^2*b^3=-3*9=-27
2a^4*b^6=a^2*b^3*2a^2*b^3=9a^2*b^3
.........................
{(х-1)/4 + у/6 = 2 | * 12
{(x+2)/6 - y/4 = - 2.5 | * 12
{ 3(x-1) + 2y = 24
{ 2(x+2) - 3y = -30
{3x - 3 + 2y = 24
{2x +4 - 3y = - 30
{3x + 2y = 24 +3
{2x - 3y = -30 - 4
{3x + 2y = 27 |*3 ⇒ у = (27 - 3х)/2
{2x - 3y = - 34 | * 2
{9x + 6y = 81
{4x - 6y = -68
Метод сложения :
9х + 6у + 4х - 6у = 81 + (-68)
13х = 13
х = 1
у = (27 - 3*1) / 2
у = 24/2
у=12
Ответ: (1 ;12)