Question

[А Л Г Е Б Р А] HELP ME)

Answer 1

$\displaystyle 36x^2-5x+d$

$\displaystyle (6x-y)^2=(6x)^2-2*6x*y+y^2$


$\displaystyle d=y^2\\\\5x=2*6x*y\\\\y= \frac{5}{12}\\\\y^2= \frac{25}{144}\\\\36x^2-5x+d=(6x)^2-2*6x* \frac{5}{12}+ \frac{25}{144}=(6x- \frac{5}{12})^2$