(70am-42m^2)-(30au-18mu)=14m*(5a-3m)-6u*(5a-3m)=(5a-3m)*(14m-6u).
A) f'(x)=(x³ +x)'=3x²+1 >0 возрастает [ ≥ 1 ]
b) f'(x)=(5x-cosx)' = 5+sinx >0 возрастает [ ≥ 4 ]
<span>c) f'(x)=(3x+cosx-sinх</span>)=3-sinx-cosx =3 -√2sin(x+π/4) >0
<span>1+7=8-100%
</span><span>100/8=12.5
</span>
<span>12.5*7=87,5%</span>