Решение
4sin(0,5x) * cos(0,5x) - √2 = 0
2sinx = √2
sinx = √2/2
x = (-1)^(n)*arcsin(√2/2) + πk, k∈Z
x = (-1)^(n)*(π/4) + πk, k∈Z
Ответ:π/3 + 2πn ≤ x ≤ 2π/3 + 2πn (где n є Z) х є [π/3 + 2πn; 2π/3 + 2πn] (где n є Z)
Объяснение:
<span>у = 0,5х^2 + 4х + 5. xmin=-b/2a=-4/1=-4 ymin=8-16+5=-3</span>
2.cos x = odm.3
cos x = odm.3/2
x = pí/6 + 2k.pí i tože x = 11pí/6 + 2k.pí
<span><span>4/5÷0,8
×(-1,25)÷(0,64-1/25)-1,2×(-0,5)
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1)
0,64-1/25=64/100-1/25=16/25-1/25=15/25=3/5
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2) 4/5:0,8=4/5:4/5=1
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3) 1*(-1,25)=-1,25
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4) -1,25:3/5=-1
1/4*5/3=-5/4*5/3=-25/12
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5) 1,2*(-0,5)=-0,6=-3/5
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6)
-25/12-(-3/5)=-25/12+3/5=-125/60+36/60=-89/60=-1 29/60
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