log 3 x + 1/2log 3 x + log 3 x <= 3
X+7>=0
5-x>0
x>=-7
-x>-5
x<5
D(y):x є [-7;5)
.........................................
<span> x² = 5x
</span><span> x²- 5x=0
х(х-5)=0
х=0 или х-5=0
х=5
ответ: </span>х=0
<em>1+sin(π+α)*cos(3π/2+α)=1+(-sinα)*sinα=1-sin²α=<u>cos²α</u>.</em>