Вроде так, в 17 не уверена
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![f(x)=4x^3\\f'(x)=12x^2\\f'(-3)=12\cdot 9=108](https://tex.z-dn.net/?f=f%28x%29%3D4x%5E3%5C%5Cf%27%28x%29%3D12x%5E2%5C%5Cf%27%28-3%29%3D12%5Ccdot%209%3D108)
(c^8)^9:c^30=c^(8*9):c^30=c^(72-30)=c^42
X³+x²+bx-24 I_x+2_
x³+2x² I x²-x-12
---------
-x²+bx
-x²-2x
---------
bx+2x-24
-12x-24
------------
0 ⇒
bx+2x-24+12x+24=0
bx+14x=0
x(b+14)=0
b+14=0
b=-14
x³+x²-14x-24 I_x+2_
x³+2x² I x²-x-12
--------
-x²-14x
-x²-2x
----------
-12x-24
-12x-24
-----------
0
x²-x-12=0 D=49
x₂=4 x₃=-3
Ответ: x₁=-2 x₂=4 x₃=-3.