(a+b)^4-(a-b)^4=[(a+b)^2-(a-b)^2][(a+b)^2+(a-b)^2]=[(a^2+2ab+b^2)-(a^2-2ab+b^2]*
[(a^2+2ab+b^2)+(a^2-2ab+b^2)] =4ab*(2a^2+2b^2)=8ab(a^2+b^2)
|5х - 4·(2х + 30)| = 6
|5x - 8x -120| = 6
|-3x - 120| = 6
-3x - 120 = 6 -3x - 120 = -6
x = -126 : 3 x = -114 : 3
x = -42 x = -38
Ответ: {-38; -42}