<span>x+2-x^2+4/x-2=? нужны скобки, непонятно, что в числителе
m-n/2mn+2/m-n=(m-n)²+2·2mn/2mn= (m-n)²+2mn/2mn(m-n)=m²-2mn+n²+4mn/2mn(m-n)=
=m²+2mn+n²/2mn(m-n)=(m+n)²/2mn(m-n)
p+3/p+4-p-3/p-4 = (p+3)/(p+4) - (p-3)/(p-4)=(p+3)(p-4)-(p+4)(p-3)/(p+4)(p-4)=
p²+3p-4p-12-p²-4p+3p+12/p²-4=-2p/p²-4
7p+q/p^2-pq+p+7q/q^2-pq</span>=(7p+q)/p(p-q)+(p+7q)/q(q-p)=(7p+q)/p(p-q)-(p+7q)/q(p-q)=(7p+q)·q-(p+7q)·p/pq(p-q)=7pq+q²-p²-7pq/pq(p-q)=(q²-p²)/pq(p-q)=-(p+q)/pq(p-q)
![x^{3} +33=-2x \\ x^{3}+2x+33=0 \\ x^{3} +11x-9x+33=0 \\ x(x^{2} -9)+11(x+3)=0 \\ x(x-3)(x+3)+11(x+3)=0 \\ (x^{2} -3x+11)(x+3)=0 \\ x+3=0 \\ x_{1} =-3 \\ x^{2} -3x+11=0 \\ D<0](https://tex.z-dn.net/?f=+x%5E%7B3%7D+%2B33%3D-2x+%5C%5C+%0A+x%5E%7B3%7D%2B2x%2B33%3D0+%5C%5C+%0A+x%5E%7B3%7D+%2B11x-9x%2B33%3D0++%5C%5C+%0A+x%28x%5E%7B2%7D+-9%29%2B11%28x%2B3%29%3D0+%5C%5C+%0Ax%28x-3%29%28x%2B3%29%2B11%28x%2B3%29%3D0+%5C%5C+%0A+%28x%5E%7B2%7D+-3x%2B11%29%28x%2B3%29%3D0+%5C%5C+%0Ax%2B3%3D0+%5C%5C+%0A+x_%7B1%7D+%3D-3+%5C%5C+%0A+x%5E%7B2%7D+-3x%2B11%3D0+%5C%5C+%0AD%3C0)
действительных корней нет
Ответ:х=-3
<span>7x - 3 +x= 4x -9 +5x
7х-4х-5х+х=3-9
-х=-6
х=6
Ответ:х=6
</span>
121 * 1/11 = 11
ответ 1/11