Question

Найдите координаты точки пересечения графиков функции y=-14x+32 y=26x-8

Answer 1

$\left \{ {{y=-14x+32} \atop {y=26x-8} \right. \left \{ {{y=-14x+32} \atop {-14x+32=26x-8} \right. \left \{ {{y=-14x+32} \atop {40=40x} \right. \left \{ {{y=-14x+32} \atop {x=1} \right. \left \{ {{y=-14*1+32} \atop {x=1} \right.$$\left \{ {{y=18} \atop {x=1} \right.$

Ответ (1;18)