х²+11х+28 =
= х² + (8х+3х) + (16+12) =
= (х²+8х+16)+(3х+12) =
= (х+4)²+3·(х+4)=
= (х+4)·(х+4+3)=
= (х+4)·(х+7)
Ответ: х²+11х+28 = (х+4)·(х+7)
.............................................
(х+6)^2
а³-8b³= a³-2³b³= a-(2b)³= (a-2b)×(a²+a×2b+(2b)²)= (a-2b)×(a²+2ab+4b²)
S=a^2sqrt(3)/4=9sqrt(3)
a=6
R=3/sin2a
sina=3/4
cosa=sqrt(1-9/16)=sqrt(7)/4
sin2a=2*sqrt(7)*3/16=3sqrt(7)/8
R=8/sqrt(7)
h^2=4^2-64/7=16-64/7=48/7
h=4*sqrt(3/7)