4.sinπ/6+3tg²π/4+cotgπ/4+2.cosπ/3=4.0,5+3.1²+1+2+0,5=
=2+3+1+0,5=6,5
(sinπ/6=cosπ/3)=0,5 , tgπ/4=cotgπ/4=1)
(a+b)*2=144
A+b=72
A=11b
11b+b=72
12b=72
B=6
A=66
√ 126 * √ 14 = √ ( 126 * 14 ) = √ ( 7 * 9 * 2 * 2 * 7 ) = 7 * 3 * 2 = 42
ОДЗ: 4x+3≠0
x≠-3/4
С учетом ОДЗ: х ∈ (-∞-;3/4)U[1.5;+∞)
Ответ: (-∞;-3/4)U[1.5;+∞)